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5n^2-9n-5=0
a = 5; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·5·(-5)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{181}}{2*5}=\frac{9-\sqrt{181}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{181}}{2*5}=\frac{9+\sqrt{181}}{10} $
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